3.2418 \(\int \frac {(a+\frac {b}{\sqrt [3]{x}})^3}{x^2} \, dx\)

Optimal. Leaf size=45 \[ -\frac {a^3}{x}-\frac {9 a^2 b}{4 x^{4/3}}-\frac {9 a b^2}{5 x^{5/3}}-\frac {b^3}{2 x^2} \]

[Out]

-1/2*b^3/x^2-9/5*a*b^2/x^(5/3)-9/4*a^2*b/x^(4/3)-a^3/x

________________________________________________________________________________________

Rubi [A]  time = 0.02, antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {263, 266, 43} \[ -\frac {9 a^2 b}{4 x^{4/3}}-\frac {a^3}{x}-\frac {9 a b^2}{5 x^{5/3}}-\frac {b^3}{2 x^2} \]

Antiderivative was successfully verified.

[In]

Int[(a + b/x^(1/3))^3/x^2,x]

[Out]

-b^3/(2*x^2) - (9*a*b^2)/(5*x^(5/3)) - (9*a^2*b)/(4*x^(4/3)) - a^3/x

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 263

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Int[x^(m + n*p)*(b + a/x^n)^p, x] /; FreeQ[{a, b, m
, n}, x] && IntegerQ[p] && NegQ[n]

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rubi steps

\begin {align*} \int \frac {\left (a+\frac {b}{\sqrt [3]{x}}\right )^3}{x^2} \, dx &=\int \frac {\left (b+a \sqrt [3]{x}\right )^3}{x^3} \, dx\\ &=3 \operatorname {Subst}\left (\int \frac {(b+a x)^3}{x^7} \, dx,x,\sqrt [3]{x}\right )\\ &=3 \operatorname {Subst}\left (\int \left (\frac {b^3}{x^7}+\frac {3 a b^2}{x^6}+\frac {3 a^2 b}{x^5}+\frac {a^3}{x^4}\right ) \, dx,x,\sqrt [3]{x}\right )\\ &=-\frac {b^3}{2 x^2}-\frac {9 a b^2}{5 x^{5/3}}-\frac {9 a^2 b}{4 x^{4/3}}-\frac {a^3}{x}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.02, size = 41, normalized size = 0.91 \[ -\frac {20 a^3 x+45 a^2 b x^{2/3}+36 a b^2 \sqrt [3]{x}+10 b^3}{20 x^2} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b/x^(1/3))^3/x^2,x]

[Out]

-1/20*(10*b^3 + 36*a*b^2*x^(1/3) + 45*a^2*b*x^(2/3) + 20*a^3*x)/x^2

________________________________________________________________________________________

fricas [A]  time = 0.72, size = 35, normalized size = 0.78 \[ -\frac {20 \, a^{3} x + 45 \, a^{2} b x^{\frac {2}{3}} + 36 \, a b^{2} x^{\frac {1}{3}} + 10 \, b^{3}}{20 \, x^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b/x^(1/3))^3/x^2,x, algorithm="fricas")

[Out]

-1/20*(20*a^3*x + 45*a^2*b*x^(2/3) + 36*a*b^2*x^(1/3) + 10*b^3)/x^2

________________________________________________________________________________________

giac [A]  time = 0.16, size = 35, normalized size = 0.78 \[ -\frac {20 \, a^{3} x + 45 \, a^{2} b x^{\frac {2}{3}} + 36 \, a b^{2} x^{\frac {1}{3}} + 10 \, b^{3}}{20 \, x^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b/x^(1/3))^3/x^2,x, algorithm="giac")

[Out]

-1/20*(20*a^3*x + 45*a^2*b*x^(2/3) + 36*a*b^2*x^(1/3) + 10*b^3)/x^2

________________________________________________________________________________________

maple [A]  time = 0.01, size = 36, normalized size = 0.80 \[ -\frac {a^{3}}{x}-\frac {9 a^{2} b}{4 x^{\frac {4}{3}}}-\frac {9 a \,b^{2}}{5 x^{\frac {5}{3}}}-\frac {b^{3}}{2 x^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+b/x^(1/3))^3/x^2,x)

[Out]

-1/2*b^3/x^2-9/5*a*b^2/x^(5/3)-9/4*a^2*b/x^(4/3)-a^3/x

________________________________________________________________________________________

maxima [A]  time = 0.52, size = 47, normalized size = 1.04 \[ -\frac {{\left (a + \frac {b}{x^{\frac {1}{3}}}\right )}^{6}}{2 \, b^{3}} + \frac {6 \, {\left (a + \frac {b}{x^{\frac {1}{3}}}\right )}^{5} a}{5 \, b^{3}} - \frac {3 \, {\left (a + \frac {b}{x^{\frac {1}{3}}}\right )}^{4} a^{2}}{4 \, b^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b/x^(1/3))^3/x^2,x, algorithm="maxima")

[Out]

-1/2*(a + b/x^(1/3))^6/b^3 + 6/5*(a + b/x^(1/3))^5*a/b^3 - 3/4*(a + b/x^(1/3))^4*a^2/b^3

________________________________________________________________________________________

mupad [B]  time = 1.12, size = 35, normalized size = 0.78 \[ -\frac {20\,a^3\,x+10\,b^3+36\,a\,b^2\,x^{1/3}+45\,a^2\,b\,x^{2/3}}{20\,x^2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b/x^(1/3))^3/x^2,x)

[Out]

-(20*a^3*x + 10*b^3 + 36*a*b^2*x^(1/3) + 45*a^2*b*x^(2/3))/(20*x^2)

________________________________________________________________________________________

sympy [A]  time = 1.18, size = 41, normalized size = 0.91 \[ - \frac {a^{3}}{x} - \frac {9 a^{2} b}{4 x^{\frac {4}{3}}} - \frac {9 a b^{2}}{5 x^{\frac {5}{3}}} - \frac {b^{3}}{2 x^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b/x**(1/3))**3/x**2,x)

[Out]

-a**3/x - 9*a**2*b/(4*x**(4/3)) - 9*a*b**2/(5*x**(5/3)) - b**3/(2*x**2)

________________________________________________________________________________________